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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-diagram based-Hard-Class 12

In a parallel plate capacitor as depicted in the NCERT figure, if the electric field between the plates is E and the surface charge density is σ\sigma, which expression correctly relates the two?

Question diagram
A

E=σε0E = \frac{\sigma}{\varepsilon_0}

B

E=ε0σE = \frac{\varepsilon_0}{\sigma}

C

E=σε0E = \sigma \varepsilon_0

D

E=1σε0E = \frac{1}{\sigma \varepsilon_0}

Correct Answer

Option A

Detailed Explanation

The NCERT context suggests the relationship E=σε0E = \frac{\sigma}{\varepsilon_0} for a parallel plate capacitor, where ε0\varepsilon_0 is the permittivity of free space.

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