Back to Practice
Physics-Potential Difference

NEET Physics Potential Difference MCQ Question

Type: MCQ-diagram based-Hard-Class 12

Consider a parallel-plate capacitor with a dielectric inserted between the plates fully occupying the region. The dielectric is polarized by the field, creating surface charge densities σp\sigma_p and −σp-\sigma_p . Which expression correctly describes the potential difference VV across the plates?

Question diagram
A

V = σ−σpε\frac{\sigma - \sigma_p}{\varepsilon} d

B

V = σ+σpε\frac{\sigma + \sigma_p}{\varepsilon} d

C

V = σε\frac{\sigma}{\varepsilon} d

D

V = σpε\frac{\sigma_p}{\varepsilon} d

Correct Answer

Option A

Detailed Explanation

The expression for potential difference when a dielectric is inserted is V=σ−σpεdV = \frac{\sigma - \sigma_p}{\varepsilon} d, where σ\sigma is the charge density on the plates and σp\sigma_p is the polarization charge density.

Found an issue with this question?

Related Questions

Explore More Questions

All Physics QuestionsElectrostatic Potential and Capacitance Questions