NEET Physics Simple Harmonic Motion MCQ Question
Consider a diagram of a mass-spring system executing simple harmonic motion on a frictionless surface. The displacement of the mass from the mean position at any instant is labeled as 'x'. What is the expression for the acceleration of the mass in terms of displacement 'x'?
a(t) = -ω^2 x(t)
a(t) = ω^2 x(t)
a(t) = -2ω x(t)
a(t) = 2ω^2 x(t)
Correct Answer
Detailed Explanation
The acceleration in simple harmonic motion is given by a(t) = -ω^2 x(t), indicating that it is proportional to displacement and directed towards the mean position.
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