NEET Physics Oscillations Class 11 Questions

In a linear simple harmonic motion (SHM) (A) Restoring force is directly proportional to the displacement. (B) The acceleration and displacement are opposite in direction. (C) The velocity is maximum at mean position. (D) The acceleration is minimum at extreme points. Choose the correct answer from the options given below:

If the frequency of human heart is 1.25 Hz, the number of heart beats in 1 minute is

A particle executing simple harmonic motion with time period T. The time period with which its kinetic energy oscillates is

The total energy of the body executing S.H.M. is E. Then the kinetic energy when the displacement is half of the amplitude, is

Two blocks each of mass m is connected to the spring of spring constant k as shown in the figure. If the blocks are displaced slightly in opposite directions and released, they will execute simple harmonic motion. The time period of oscillation is

A particle executing SHM according to the equation \( x = 5 \cos \left( 2\pi t + \frac{\pi}{4} \right) \) in SI units. The displacement and acceleration of the particle at \( t = 1.5 \) s is

The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is

The displacement of a particle varies with time according to the relation y = a sin ωt + b cos ωt.

The piston in the cylinder head of a locomotive has a stroke of 6 m. If the piston executing simple harmonic motion with an angular frequency of 200 rad min⁻¹, its maximum speed is

A particle is in linear simple harmonic motion between two points A and B, 10 cm apart (figure). Take the direction from A to B as the +ve direction. Which of the following statements is correct?

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of increased length is

The angular frequency of kinetic energy of simple harmonic oscillator is 176 rad/s, then the frequency of simple harmonic oscillator will be:

The time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 ms⁻¹. The amplitude is

For a simple pendulum, having time period T, the variation of kinetic energy (K.E.) with time (t) is represented by:

Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as: (Take π² = 9.8, and g = 9.8 m/s²)

In an oscillating spring mass system, a spring is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency ω(t) and average amplitude A(t) of the system change with time t. Which one of the following options schematically depicts these changes correctly?

Two identical point masses P and Q, suspended from two separate massless springs of spring constants k₁ and k₂, respectively, oscillate vertically. If their maximum speeds are the same, the ratio (A₀Q/A₀P) of the amplitude A₀Q of mass Q to the amplitude A₀P of mass P is:

If \( x = 5 \sin \left( \pi t + \frac{\pi}{3} \right) \) m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are:

If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is x/2 times its original time period. Then the value of x is:

The <em>x</em>-<em>t</em> graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at <em>t</em> = 2 s is:

Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

A body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is:

A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is :

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :

The displacement of a particle executing simple harmonic motion is given by y = A₀ + A sin ωt + B cos ωt. Then the amplitude of its oscillation is given by:

Average velocity of a particle executing SHM in one complete vibration is:

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s² at a distance of 5 m from the mean position. The time period of oscillation is

A spring of force constant k is cut into lengths of ratio 1:2:3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k''. Then k' : k'' is

A particle is executing S.H.M along a straight line. Its velocities at distances x₁ and x₂ from the mean position are v₁ and v₂ respectively. Its time period is

When two displacements represented by y₁ = a sin(ωt) and y₂ = b cos(ωt) are superimposed the motion is

The oscillation of a body on a smooth horizontal surface is represented by the equation, X = Acos(ωt) where, X = displacement at time t, ω = frequency of oscillation. Which one of the following graphs shows correctly the variation a with t? Here a = acceleration at time t, T = time period

A particle of mass m oscillates along X⁻axis according to equation x = a sin ωt. The nature of the graph between momentum and displacement of the particle is: