NEET Physics Simple Harmonic Motion MCQ Question
The piston in the cylinder head of a locomotive has a stroke of 6 m. If the piston executing simple harmonic motion with an angular frequency of 200 rad min⁻¹, its maximum speed is
5 m s⁻¹
10 m s⁻¹
15 m s⁻¹
20 m s⁻¹
Correct Answer
Detailed Explanation
The maximum speed in simple harmonic motion is given by v_max = ωA. Here, ω = 200 rad min⁻¹ = (200/60) rad s⁻¹ and A = 3 m, so v_max = (200/60) * 3 = 10 m s⁻¹.
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