NEETPhysics-Oscillations
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
The time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 ms⁻¹. The amplitude is
A
44 m
B
0.72 m
C
88 m
D
0.36 m
Correct Answer
Option C
Detailed Explanation
Using the formula for velocity in SHM, v = ω√(A² - x²), and given values, the amplitude A can be calculated.
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