NEETPhysics-Oscillations

NEET Physics Simple Harmonic Motion MCQ Question

Type: MCQ-numerical-Medium-Class 11

The time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 ms⁻¹. The amplitude is

A

44 m

B

0.72 m

C

88 m

D

0.36 m

Correct Answer

Option C

Detailed Explanation

Using the formula for velocity in SHM, v = ω√(A² - x²), and given values, the amplitude A can be calculated.

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