NEET Chemistry Solubility Product MCQ Question
What is the molar solubility (S) of a salt with formula A2X3 in pure water if its solubility product Ksp is 1.1 × 10⁻²³?
6 × 10⁻⁶ M
1 × 10⁻²³ M
3 × 10⁻⁶ M
5.2 × 10⁻⁶ M
Correct Answer
Detailed Explanation
Using Ksp = [A³⁺]²[X²⁻]³ and the stoichiometry A2X3 → 2A³⁺ + 3X²⁻, we find S = (Ksp / (2² × 3³))^(1/5).
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