Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
Given the ionization constant (Ka) of HF as 3.5 × 10^–4 at 298 K, calculate the pH of a 0.02 M HF solution using the degree of ionization.
A
15
B
23
C
85
D
45
Correct Answer
Option C
Detailed Explanation
The degree of ionization can be calculated using the formula: α = sqrt(Ka/C), where C is the concentration of HF. Substituting the given values, α = sqrt((3.5 × 10^–4)/(0.02)) gives the concentration of H3O+. The pH can then be calculated as -log[H3O+].
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