STANDARDChemistry-Solubility Product
STANDARD Chemistry Calculating Solubility MCQ Question
Type: MCQ-numerical-Medium
The solubility product of BaCl₂ is 3.2 × 10⁻⁹. What will be its solubility in mol L⁻¹?
A
4 × 10⁻³
B
3.2 × 10⁻⁹
C
1 × 10⁻³
D
1 × 10⁻⁹
Correct Answer
Option C
Detailed Explanation
BaCl₂ ⇌ Ba²⁺ + 2Cl⁻. Kₛₚ = [Ba²⁺][Cl⁻]² = x × (2x)² = 4x³. Solving 4x³ = 3.2 × 10⁻⁹ gives x ≈ 1 × 10⁻³ mol L⁻¹.
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