Chemistry-Solubility Product
NEET Chemistry Solubility Product MCQ Question
Type: MCQ-numerical-Medium-Class 11
Calculate the molar solubility of barium sulfate (BaSO4) in water at 298 K, given that the solubility product (Ksp) is 1.1 × 10^-10.
A
05 × 10^-5 M
B
20 × 10^-5 M
C
32 × 10^-6 M
D
10 × 10^-5 M
Correct Answer
Option A
Detailed Explanation
For the dissolution of BaSO4, Ksp = [Ba^2+][SO4^2-] = s^2. Solving s^2 = 1.1 × 10^-10 gives s = 1.05 × 10^-5 M.
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