STANDARD Physics Young's Double Slit Experiment MCQ Question
The slits in Young's double slit experiment are illuminated by light of wavelength 6000 Å. If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe?
2.4 × 10⁻⁶ m
1.2 × 10⁻⁶ m
10⁻⁶ m
0.5 × 10⁻⁶ m
Correct Answer
Detailed Explanation
The path difference at the centre is zero. The path difference at the 4th bright fringe = 4λ. Here, λ = 6000 × 10⁻¹⁰ m. Path difference = 4 × 6000 × 10⁻¹⁰ = 24 × 10⁻⁷ m = 2.4 × 10⁻⁶ m.
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