STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central and fourth bright fringe is measured to be 1.2 cm. The wavelength of light used in the experiment is
6 × 10⁻⁷ m
3 × 10⁻⁷ m
1.5 × 10⁻⁷ m
5 × 10⁻⁶ m
Correct Answer
Detailed Explanation
Using the formula for fringe separation, Δy = λL/d, where Δy = 1.2 cm, L = 1.4 m, and d = 0.28 mm, solving for λ gives 6 × 10⁻⁷ m.
Found an issue with this question?
Related Questions
More from
What condition must be met for constructive interference to occur at a point P from two coherent sources S1 and S2?
Which of the following statements about Young's Double Slit experiment is correct?
What is the condition for destructive interference in terms of path difference between two coherent sources?