STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment, the 10th maximum of wavelength λ₁ is at a distance y₁ from its central maximum and the 5th maximum of wavelength λ₂ is at a distance y₂ from its central maximum. The ratio y₁/y₂ will be
2λ₂/λ₁
2λ₁/λ₂
λ₁/2λ₂
λ₂/2λ₁
Correct Answer
Detailed Explanation
We know that position of mᵗʰ bright fringe is yₘ = mλD/d. Therefore, for wavelength λ₁, y₁ = 10λ₁D/d and for wavelength λ₂, y₂ = 5λ₂D/d. Thus, y₁/y₂ = 2λ₁/λ₂.
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