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STANDARD Chemistry Molarity and Ion Concentration MCQ Question

Type: MCQ-numerical-Medium-Class 12

How many Na⁺ ions are present in 100 mL of 0.25 M of NaCl solution?

A

0.025 × 10²³

B

1.505 × 10²²

C

15 × 10²²

D

2.5 × 10²³

Correct Answer

Option B

Detailed Explanation

The number of moles of NaCl is calculated using Molarity (M) = 0.25 mol/L and Volume (V) = 0.1 L, resulting in 0.025 mol of NaCl. Since each mole of NaCl produces one mole of Na⁺ ions, the number of Na⁺ ions is 0.025 × 6.023 × 10²³ = 1.505 × 10²².

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