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STANDARD Chemistry Colligative Properties MCQ Question

Type: MCQ-numerical-Medium-Class 12

1 g of solute (molar mass = 50 g mol⁻¹) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molal elevation constant of the solvent is

A

2

B

3

C

2.5

D

5

Correct Answer

Option C

Detailed Explanation

The molal elevation constant (K_b) is calculated using the formula ΔT_b = K_b × m, where m is the molality. Here, ΔT_b = 1 K, and m = (1/50) × 1000 = 20 mol/kg. Thus, K_b = 1/20 = 0.05 K kg/mol.

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