NEET Physics Interference MCQ Question
In a double-slit experiment, the distance between the slits (d) is 0.025 mm, the screen is placed at a distance (D) of 5 cm, and the wavelength of light (λ) used is 5 × 10^-5 cm. What is the distance (x) from the central maximum to the first order bright fringe?
0 mm
0.5 mm
0 mm
0.25 mm
Correct Answer
Detailed Explanation
Using the formula x = nDλ/d for constructive interference, where n = 1 for first-order, x = (1)(5 cm)(5 × 10^-5 cm) / 0.025 mm = 1.0 mm.
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