Physics-Interference

NEET Physics Interference MCQ Question

Type: MCQ-numerical-Medium-Class 12

In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5 × 10^-5 cm. What is the distance of the second bright fringe from the central maximum?

A

0.2 mm

B

0.25 mm

C

0.5 mm

D

0.75 mm

Correct Answer

Option C

Detailed Explanation

Using the formula x_n = n * D * λ / d, where n = 2 for the second bright fringe, D = 5 cm, λ = 5 × 10^-5 cm, and d = 0.025 mm = 0.0025 cm, we find x_2 = 0.5 mm.

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