NEET Physics Young's Double Slit MCQ Question
In Young's Double Slit Experiment, if the distance between the slits is 0.5 mm and the distance to the screen is 1.5 m, what is the fringe width for light of wavelength 589 nm?
767 mm
0.589 mm
0.176 mm
589 mm
Correct Answer
Detailed Explanation
The fringe width (β) can be calculated using the formula β = λD/d, where λ is the wavelength, D is the distance to the screen, and d is the distance between the slits. Substituting the given values, β = (589 × 10^-9 m)(1.5 m)/(0.5 × 10^-3 m) = 1.767 mm.
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