Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 12
In a semiconductor, if the intrinsic carrier concentration is 2.25 × 10^32 m^-3 and the donor concentration is 5 × 10^22 m^-3, what is the concentration of holes?
A
5 × 10^9 m^-3
B
5 × 10^10 m^-3
C
5 × 10^8 m^-3
D
5 × 10^9 m^-3
Correct Answer
Option A
Detailed Explanation
Using the relation n_e * n_h = n_i^2, where n_i is the intrinsic carrier concentration and n_e is the donor concentration, we calculate n_h = (2.25 × 10^32) / (5 × 10^22) = 4.5 × 10^9 m^-3.
Found an issue with this question?