NEET Physics Nuclear Forces MCQ Question
Consider a heavy nucleus with mass number A = 240 that splits into two nuclei with A = 120 each. If the binding energy per nucleon of the original and resultant nuclei are 7.6 MeV and 8.5 MeV respectively, what is the total energy released in this fission process?
216 MeV
360 MeV
204 MeV
408 MeV
Correct Answer
Detailed Explanation
The energy released is the difference in total binding energy before and after fission. Initial binding energy = 240 * 7.6 MeV. Final binding energy = 2 * 120 * 8.5 MeV. The difference is the energy released.
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