NEET Physics Nuclear Forces MCQ Question
Consider a nucleus with a mass number A = 240 undergoing fission into two nuclei each with A = 120. If the initial binding energy per nucleon of A = 240 is 7.5 MeV and the final binding energy per nucleon of A = 120 is 8.5 MeV, what is the total energy released in the fission process?
240 MeV
480 MeV
960 MeV
1920 MeV
Correct Answer
Detailed Explanation
The energy released is the difference in total binding energy before and after fission. Initial total binding energy is 240 * 7.5 MeV, and final total binding energy is 2 * 120 * 8.5 MeV. The difference is the energy released.
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