Physics-Nuclear Forces
NEET Physics Nuclear Forces MCQ Question
Type: MCQ-numerical-Hard-Class 12
Consider a nucleus with a mass number A = 240 undergoing fission into two nuclei each with A = 120. If the initial binding energy per nucleon of A = 240 is 7.5 MeV and the final binding energy per nucleon of A = 120 is 8.5 MeV, what is the total energy released in the fission process?
A
240 MeV
B
480 MeV
C
960 MeV
D
1920 MeV
Correct Answer
Option B
Detailed Explanation
The energy released is the difference in total binding energy before and after fission. Initial total binding energy is 240 * 7.5 MeV, and final total binding energy is 2 * 120 * 8.5 MeV. The difference is the energy released.
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