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Physics-Potential Difference

NEET Physics Potential Difference MCQ Question

Type: MCQ-diagram based-Medium-Class 12

Consider a parallel-plate capacitor with a dielectric fully inserted between the plates. Describe the potential difference across the plates in terms of the surface charge density σ\sigma, polarisation surface charge density σp\sigma_p, and permittivity ε0\varepsilon_0. Which equation correctly represents this relationship?

Question diagram
A

V = σ−σpε0\frac{\sigma - \sigma_p}{\varepsilon_0} d

B

V = σε0\frac{\sigma}{\varepsilon_0} d

C

V = σ+σpε0\frac{\sigma + \sigma_p}{\varepsilon_0} d

D

V = σε0\frac{\sigma}{\varepsilon_0} (d + \sigma_p)

Correct Answer

Option A

Detailed Explanation

The potential difference across the plates with a dielectric inserted is given by V=σ−σpε0V = \frac{\sigma - \sigma_p}{\varepsilon_0} d, reflecting the reduction in net charge density due to polarisation.

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