NEET Physics (general) Match the Following Question
Match Column-I with Column-II.
Column-I Column-II (a) Electrostatic energy in a capacitor (i) 0.5 × C × V² (b) Effect of inserting dielectric (ii) Increases capacitance (c) Energy loss in charge sharing (iii) Decreases voltage (d) Work done against electric field (iv) Charge × Potential difference
Choose the correct matching:
a-i, b-ii, c-iii, d-iv
a-ii, b-i, c-iv, d-iii
a-iv, b-iii, c-i, d-ii
a-iii, b-iv, c-ii, d-i
Correct Answer
Detailed Explanation
The electrostatic energy stored in a capacitor is given by the formula 0.5 × C × V². Inserting a dielectric increases capacitance, which is a well-known property of dielectrics. The work done against the electric field is calculated as Charge × Potential difference.
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