NEET2026Physics-Electrostatics
NEET 2026 Physics Capacitors MCQ Question
Type: MCQ-numerical-Medium-Class 12
Consider two uncharged capacitors of equal capacitance 200 pF. One of them is charged by a 100 V supply and disconnected. Now this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:
A
0.5 × 10⁻⁶ J
B
1.0 J
C
1.0 × 10⁻⁶ J
D
0.5 J
Correct Answer
Option A
Detailed Explanation
The energy loss is calculated using the formula: Energy loss = 1/2 × (C₁C₂ / (C₁ + C₂)) × V². Substituting the given values, the energy loss is 0.5 × 10⁻⁶ J.
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