NEET 2026 Physics Combination of Capacitors MCQ Question

Topic: Capacitance → Combination of Capacitors Difficulty: 🟡 Medium

✅ Ans: B → $5\,\mu F,\;125\,\mu C$ on all capacitors

First, $C_1,C_2,C_3,C_4$ are four identical capacitors in series:

$$C_s=\frac{10}{4}=2.5\,\mu F$$

This is in parallel with $C_5=2.5\,\mu F$:

$$C_{eq}=2.5+2.5=\boxed{5\,\mu F}$$

Total charge:

$$Q=C_{eq}V=5\times50=\boxed{250\,\mu C}$$

Since the two parallel branches each have $50V$:

For series branch:

$$Q_s=C_sV=2.5\times50=\boxed{125\,\mu C}$$

In a series combination, charge on each capacitor is the same.

Thus:

$$\boxed{Q_{C_1}=Q_{C_2}=Q_{C_3}=Q_{C_4}=Q_{C_5}=125\,\mu C}$$

🧠 NEET Trick

Series → same charge Parallel → same potential difference

⚠️ The screenshot marks A, but the calculation gives B.