Physics-Power in AC Circuits
NEET Physics Power in AC Circuits MCQ Question
Type: MCQ-numerical-Medium-Class 12
A series RLC circuit is connected to an AC source with a peak voltage of 300 V. If the impedance Z of the circuit is 150 Ω and the phase angle φ is 30°, what is the average power consumed by the circuit?
A
300 W
B
325 W
C
450 W
D
600 W
Correct Answer
Option A
Detailed Explanation
The average power is given by P = V_rms * I_rms * cos(φ). Here, V_rms = V_m/√2 = 300/√2 V and I_rms = V_rms/Z = (300/√2)/150 A. Therefore, P = (300/√2) * ((300/√2)/150) * cos(30°) = 300 W.
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