NEET Physics Transverse & Longitudinal Waves MCQ Question
A string of length 2 meters is fixed at both ends and is vibrating in its fundamental mode with a frequency of 50 Hz. If the mass of the string is 0.04 kg, what is the tension in the string?
200 N
400 N
800 N
1000 N
Correct Answer
Detailed Explanation
The frequency of the fundamental mode for a string fixed at both ends is given by f = (1/2L)√(T/μ), where L is the length, T is the tension, and μ is the mass per unit length. Solving for T using the given values (L = 2 m, f = 50 Hz, and μ = 0.02 kg/m), we get T = 400 N.
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