Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Medium-Class 11
Calculate the change in Gibbs free energy (∆G) for a reaction at 300 K with an equilibrium constant of 10. Use the relation ∆G = -RT ln K.
A
-5.7 kJ mol⁻¹
B
-8.3 kJ mol⁻¹
C
-24.2 kJ mol⁻¹
D
-12.4 kJ mol⁻¹
Correct Answer
Option A
Detailed Explanation
Using the relation ∆G = -RT ln K, where R = 8.314 J K⁻¹ mol⁻¹, T = 300 K, and K = 10, the calculation gives ∆G = -8.314 * 300 * ln(10) J mol⁻¹ = -5.7 kJ mol⁻¹.
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