NEET Physics Isothermal & Adiabatic Processes MCQ Question
In an adiabatic process involving an ideal gas, which of the following expressions correctly represents the work done (w) on the gas, given that q = 0?
w = ∆U
w = nRT ln(Vf/Vi)
w = 2.303 nRT log(Vf/Vi)
w = -pex ∆V
Correct Answer
Detailed Explanation
In an adiabatic process, q = 0, so the change in internal energy (∆U) is equal to the work done on the system (w).
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