Physics-Simple Harmonic Motion
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A particle executes simple harmonic motion described by the equation x(t) = A cos(ωt). If the angular frequency ω is 5 rad/s, what is the period of this motion?
A
1.26 s
B
0.63 s
C
1.57 s
D
0.31 s
Correct Answer
Option B
Detailed Explanation
The period T of the motion is given by T = 2π/ω. Substituting ω = 5 rad/s gives T = 2π/5 = 0.63 s, as derived from NCERT context Chunk 3.
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