Physics-Simple Harmonic Motion
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
A particle is executing simple harmonic motion between two points, A and B, 10 cm apart. What is the velocity of the particle when it is 3 cm away from point A moving towards B, given the maximum velocity is 10 cm/s?
A
8 cm/s
B
6 cm/s
C
4 cm/s
D
2 cm/s
Correct Answer
Option B
Detailed Explanation
Using the relationship for SHM, v = v_max * sqrt(1 - (x^2 / A^2)), where A is the amplitude (5 cm) and x is the displacement from the mean position (2 cm from the mean since 3 cm from A). Thus, v = 10 * sqrt(1 - (2/5)^2) = 6 cm/s.
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