NEET Physics Simple Harmonic Motion MCQ Question
A simple pendulum with a mass of 5 kg is oscillating with a small angular displacement. If the length of the pendulum is 2 meters and the acceleration due to gravity is 9.8 m/s², what is the approximate angular frequency of the pendulum's simple harmonic motion?
21 rad/s
13 rad/s
57 rad/s
05 rad/s
Correct Answer
Detailed Explanation
The angular frequency ω of a simple pendulum is given by ω = √(g/L). For g = 9.8 m/s² and L = 2 m, ω = √(9.8/2) = √4.9 ≈ 2.21 rad/s.
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