NEET Physics Simple Harmonic Motion MCQ Question
A block of mass m is attached to two identical springs, each with a spring constant k, on a frictionless horizontal surface. If the system is displaced slightly and released, what is the time period T of the resulting simple harmonic motion?
2π√(m/2k)
2π√(m/k)
2π√(m/4k)
2π√(m/3k)
Correct Answer
Detailed Explanation
According to the given context, the net force acting on the mass is F = -2kx, as two springs are involved. The effective spring constant is 2k, leading to T = 2π√(m/2k) for the time period of oscillation.
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