NEET2019Physics-Oscillations
NEET 2019 Physics Simple Harmonic Motion MCQ Question
Type: MCQ-conceptual-Medium-Class 11
The displacement of a particle executing simple harmonic motion is given by y = A₀ + A sin ωt + B cos ωt. Then the amplitude of its oscillation is given by:
A
√(A₀² + (A⁺B)²)
B
A + B
C
A₀ + √(A² + B²)
D
√(A² + B²)
Correct Answer
Option D
Detailed Explanation
The amplitude of SHM is the square root of the sum of the squares of the coefficients of sin and cos terms.
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