AIIMS2019Physics-Oscillations

AIIMS 2019 Physics Damped Oscillations MCQ Question

Type: MCQ-conceptual-Medium-Class 11

mx2bx+k=0mx^2 - bx + k = 0

Find time after which to the energy will become half of initial maximum value in damped force oscillation.

A

t=mb+12ln2t = \frac{m}{b} + \frac{1}{2}\ln 2

B

t=mb×23ln2t = \frac{m}{b} \times \frac{2}{3}\ln 2

C

t=mb12ln2t = \frac{m}{b} - \frac{1}{2}\ln 2

D

t=mb×12ln2t = \frac{m}{b} \times \frac{1}{2}\ln 2

Correct Answer

Option D

Detailed Explanation

In damped forced oscillations, the energy of the system decreases exponentially over time, described by the equation E(t)=E0ebt/mE(t) = E_0 e^{-bt/m}. To find the time tt when the energy becomes half of its initial value, we set E(t)=12E0E(t) = \frac{1}{2} E_0 and solve for tt, leading to the expression t=mbln2t = \frac{m}{b} \ln 2. This matches option D, which correctly represents the relationship between mass mm, damping constant bb, and the natural logarithm of 2. The other options are incorrect as they do not accurately reflect the mathematical derivation or the exponential decay behavior of energy in damped oscillations.

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