For a cell involving one electron E°cell=0.59 V at 298 K, the equilibrium constant for the cell reaction is [Given that $\frac{2.303RT}{F} = 0.059 \text{ V at } T = 298 \text{ K}$ ]
A
1.0 × 10⁵
B
1.0 × 10¹⁰
C
1.0 × 10³⁰
D
1.0 × 10²

Question

For a cell involving one electron E°cell=0.59 V at 298 K, the equilibrium constant for the cell reaction is [Given that $ \frac{2.303RT}{F} = 0.059 \text{ V at } T = 298 \text{ K} $]

Accepted Answer

1.0 × 10¹⁰

Answer

1.0 × 10⁵

Answer

1.0 × 10³⁰

Answer

1.0 × 10²

NEET 2019 Chemistry Nernst Equation MCQ Question

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