NEET 2019 Chemistry Gibbs Free Energy MCQ Question
For the cell reaction, 2Fe³⁺(aq) + 2I⁻(aq) → 2Fe²⁺(aq) + I₂(aq), E°cell = 0.24 V at 298 K. The standard Gibbs energy (ΔG°) of the cell reaction is [Given that Faraday constant F = 96500 C mol⁻¹]
−23.16 kJ mol⁻¹
46.32 kJ mol⁻¹
23.16 kJ mol⁻¹
−46.32 kJ mol⁻¹
Correct Answer
Detailed Explanation
ΔG° = −nFE°cell. For the given reaction, n = 2, F = 96500 C mol⁻¹, and E°cell = 0.24 V, so ΔG° = −23.16 kJ mol⁻¹.
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