NEET Chemistry Faraday's Laws MCQ Question
An electric charge of 5 Faradays is passed through three electrolytes AgNO₃, CuSO₄ and FeCl₃ solution. The grams of each metal liberated at cathode will be
Ag = 10.8 g, Cu = 12.7 g, Fe = 1.11 g
Ag = 540 g, Cu = 367.5 g, Fe = 325 g
Ag = 108 g, Cu = 63.5 g, Fe = 56 g
Ag = 540 g, Cu = 158.8 g, Fe = 93.3 g
Correct Answer
Detailed Explanation
The mass of metal liberated is calculated using Faraday's laws of electrolysis: mass = (Equivalent weight × Current × Time) / Faraday's constant. For 5 Faradays, the mass is directly proportional to the equivalent weight.
Found an issue with this question?
Related Questions
More from Electrochemistry
The molar conductivity of 0.007 M acetic acid is 20 S cm² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option. [Λ°_H⁺ =...
The molar conductance of NaCl, HCl and CH₃COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm² mol⁻¹ respectively. The molar conductance of CH...
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R: Assertion A: In equation ΔrG = −nFEcell, value ...
More from
Calculate the dissociation constant \( K_a \) for acetic acid given that its conductivity is \( 4.95 \times 10^{-5} \text{ S cm}^{-1} \) at a concentr...
Match Column-I with Column-II. Column-I Column-II (a) Cathode reaction (i) Cu 2+ (aq) + 2e – → Cu (s) (b) Anode reaction (ii) Cu(s) ...