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Chemistry-Rate of Reaction

NEET Chemistry Rate of Reaction MCQ Question

Type: MCQ-numerical-Medium-Class 12

Given the rate constants of a reaction are 0.02 s⁻¹ at 500 K and 0.07 s⁻¹ at 700 K, what is the activation energy (Ea) for this reaction in J/mol?

A

35000

B

42000

C

50000

D

60000

Correct Answer

Option B

Detailed Explanation

Using the formula log⁡k2k1=Ea2.303R(1T1−1T2)\log \frac{k_2}{k_1} = \frac{E_a}{2.303R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right), and substituting given values, Ea is calculated as 42000 J/mol.

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