MarksRiser
MarksRiser
Chemistry-Gibbs Free Energy

NEET Chemistry Gibbs Free Energy MCQ Question

Type: MCQ-numerical-Medium-Class 11

Calculate the standard Gibbs free energy change (∆rG°) for the following reaction at 298 K, given that the equilibrium constant (Kp) for the reaction is 3.14 × 10⁻²: 2NO(g) + O₂(g) ⇌ 2NO₂(g).

A

-7.16 kJ mol⁻¹

B

-5.89 kJ mol⁻¹

C

-8.63 kJ mol⁻¹

D

-6.45 kJ mol⁻¹

Correct Answer

Option A

Detailed Explanation

Using the formula ∆rG° = -RT ln Kp, where R = 8.314 J K⁻¹ mol⁻¹ and T = 298 K, the calculation gives ∆rG° = -7.16 kJ mol⁻¹.

Found an issue with this question?