NEET Chemistry Chemical Equilibrium MCQ Question
For the equilibrium reaction N2(g) + 3H2(g) ⇌ 2NH3(g) at 500K, given that [N2] = 1.5 × 10^-2 M, [H2] = 3.0 × 10^-2 M, and [NH3] = 1.2 × 10^-2 M, what is the equilibrium constant Kc?
3.55 × 10^2
0.355 × 10^3
3.0 × 10^2
0.355
Correct Answer
Detailed Explanation
Using the given concentrations, Kc = ([NH3]^2) / ([N2][H2]^3) = (1.2 × 10^-2)^2 / (1.5 × 10^-2 * (3.0 × 10^-2)^3) = 3.55 × 10^2.
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