NEET Chemistry Ionization Energy MCQ Question
Calculate the ionization enthalpy of atomic hydrogen in kJ mol⁻¹ using the energy of its electron in the ground state given as –2.18×10⁻¹⁸ J. (1 J = 10⁻³ kJ, Avogadro's number = 6.022×10²³ mol⁻¹)
1312
2180
1090
436
Correct Answer
Detailed Explanation
The ionization enthalpy can be calculated by multiplying the energy of the electron (-2.18×10⁻¹⁸ J) by Avogadro's number (6.022×10²³ mol⁻¹) and converting J to kJ. This results in approximately 1312 kJ mol⁻¹.
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