NEET Chemistry Ionization Energy MCQ Question
Calculate the ionization enthalpy of atomic hydrogen in terms of kJ mol-1 if the energy of an electron in the ground state of the hydrogen atom is -2.18×10-18 J.
1312 kJ mol-1
2180 kJ mol-1
1090 kJ mol-1
1500 kJ mol-1
Correct Answer
Detailed Explanation
The ionization enthalpy of hydrogen is calculated using the energy of the electron and Avogadro's number (6.022×10^23 mol-1): -2.18×10-18 J × 6.022×10^23 mol-1 = 1312 kJ mol-1.
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