NEET Chemistry Ionization Energy MCQ Question
Calculate the ionization enthalpy of a hydrogen atom in the ground state given that the energy of an electron in this state is -2.18×10⁻¹⁸ J. Use Avogadro's number (6.022×10²³ mol⁻¹) for conversion.
31 × 10⁶ J mol⁻¹
18 × 10⁻¹⁸ J mol⁻¹
31 × 10³ J mol⁻¹
18 × 10⁶ J mol⁻¹
Correct Answer
Detailed Explanation
The ionization enthalpy is calculated by multiplying the energy of one electron (-2.18 × 10⁻¹⁸ J) by Avogadro's number (6.022 × 10²³ mol⁻¹), resulting in 1.31 × 10⁶ J mol⁻¹.
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