NEET Chemistry Ionization Energy MCQ Question
Calculate the ionization enthalpy of atomic hydrogen in kJ mol⁻¹, given that the energy of an electron in the ground state of hydrogen is -2.18×10⁻¹⁸ J.
1.31 × 10³ kJ mol⁻¹
1.31 × 10² kJ mol⁻¹
1.31 × 10⁴ kJ mol⁻¹
1.31 kJ mol⁻¹
Correct Answer
Detailed Explanation
The ionization enthalpy is calculated by converting the energy per atom in J (–2.18×10⁻¹⁸ J) to energy per mole, using Avogadro's number: (–2.18×10⁻¹⁸ J/atom) × (6.022×10²³ atoms/mol) = 1.31 × 10³ kJ mol⁻¹.
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