Power dissipated in an LCR series circuit connected to an a.c source of emf ε is:

Question

Accepted Answer

\frac{\varepsilon^2R}{R^2+\left(L\omega-\frac{1}{C\omega}\right)^2}

Answer

\frac{\varepsilon^2\sqrt{R^2+\left(L\omega-\frac{1}{C\omega}\right)^2}}{R}

Answer

\frac{\varepsilon^2\left[R^2+\left(L\omega-\frac{1}{C\omega}\right)^2\right]}{R}

Answer

\frac{\varepsilon^2R}{\sqrt{R^2+\left(L\omega-\frac{1}{C\omega}\right)^2}}

AIPMT PRELIMS 2009 Physics Power in AC Circuits MCQ Question