AIPMT PRELIMS 2010 Physics Conservation of Momentum MCQ Question
A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be
20 m
9.9 m
10.1 m
10 m
Correct Answer
Detailed Explanation
In a gravity-free space, the center of mass of the system remains constant. Initially, the center of mass is at 10 m. After the stone is thrown, the man moves upwards due to conservation of momentum. The distance moved by the man is calculated using the conservation of momentum principle, resulting in a final distance of 10.1 m.
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