AIPMT MAINS 2010 Physics Conservation of Angular Momentum MCQ Question
A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity ω. Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by
(M+2m)ω/2m
2Mω/M+2m
(M+2m)ω/M
Mω/M+2m
Correct Answer
Detailed Explanation
The moment of inertia of the system changes when the masses are added. Using conservation of angular momentum, I₁ω₁ = I₂ω₂, where I₁ = MR² and I₂ = (M+2m)R², we find ω₂ = Mω/(M+2m).
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