MarksRiser
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AIPMT MAINS2009Physics-Rotational Motion

AIPMT MAINS 2009 Physics Conservation of Angular Momentum MCQ Question

Type: MCQ-numerical-Medium-Class 11

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity:

A

ωM/(M + 2m)

B

(ω(M + 2m))/M

C

ωM/(M + m)

D

(ω(M - 2m))/(M + 2m)

Correct Answer

Option A

Detailed Explanation

The conservation of angular momentum applies here. The initial angular momentum is I₁ω = MR²ω. After attaching the masses, the new moment of inertia is I₂ = MR² + 2mR². Solving for the new angular velocity gives ω' = ωM/(M + 2m).

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