AIIMS 2019 Physics Ideal Gas Law MCQ Question

To find the final pressure of the ideal gas, we can use the ideal gas law, $PV = nRT$. Given the initial conditions $P_1 = 1 \, \text{bar}$, $V_1 = 30 \, \text{m}^3$, $T_1 = 320 \, \text{K}$, and the final conditions $V_2 = 10 \, \text{m}^3$, $T_2 = 280 \, \text{K}$, we can relate the pressures using the formula $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$. Solving this gives $P_2 = \frac{P_1 V_1 T_2}{V_2 T_1} = \frac{1 \, \text{bar} \times 30 \, \text{m}^3 \times 280 \, \text{K}}{10 \, \text{m}^3 \times 320 \, \text{K}} = 2.625 \, \text{bar}$.

Options B (3.4 bar), C (1.325 bar), and D (4.5 bar) are incorrect as they do not satisfy the ideal gas law under the given conditions, indicating a